PROBLEM 2 GIVEN S KIET E 29000 ksi 3 9 Solutionuniform load

PROBLEM 2) GIVEN S KIET E 29,000 ksi 3\' 9

Solution

uniform load on beam=35 kip/ft=2.917 kip/in

E=29000 ksi

I=2000 in⁴

span of beam=12 ft=12*12=144 in

distance AB=3 ft=3*12=36 in

vertical deflection is given by (2.917*36)(144³-2*144*36²+36³)/(24*29000*2000) = 0.2 in

Correct answer is 0.2 in