find the equation of the line in a slope intercept form ymxb
find the equation of the line in a slope intercept form y=mx+b , with points; a) (0,-5), (-3,-5)
b) (-3,-5), (-5,-5)
Solution
a) (0,-5), (-3,-5)
slope m = (y2-y1)/(x2-x1) = 0
the equation of the line y + 5 = 0 ==> y = -5
b) (-3,-5), (-5,-5)
slope m = (y2-y1)/(x2-x1) = 0
the equation of the line y + 5 = 0 ==> y = -5
