Assessment Problem 2 Determine the voltage V and current 2 F
Solution
total current in circuit = 8mA
let us determine total resistabce of circuit
resistors 4.8k-Ohms and 3.2k-Ohms are in series .Their total resistnace = 4.8+3.2=8k-Ohms
This is in parallel to 8k-Ohms .Their totak resistnace = (8*8)/(8+8)=4 k-Ohms
this is series with 4k-Ohms
Therefore,totak resistance of circuit = 4+4=8k-Ohms
Total current in circuit = 8mA
therefore, battery voltage = 8*10-3*8*103=64 Volts
current I2 = 8/2=4 mA because the current 8 mA will get equally distributed to branch of 8 k-Ohms and brance of 4.8 and 3.2 k-Ohms resitors since the two branches have equal resistance
Therefore, I2 = 4mA
