67ta 13 C410uF C34UE Z 2 FE 547 Z SolutionCequ c1 and c2 a

-67----ta- 13 -C-4-----10-uF C34UE Z !! 2 FE 547 Z

Solution

C_equ = (c1 and c2 are in parallel) + c3

C₁₂ = 10 + 5 = 15 muF

1/C_equ = 1/15 + 1/4

C_equ = 3.16 muF

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V₁ = V₂ = V * C₃ / C₁₂ + C₃

= 12 * 4 / (4 + 15)

V₁ = V₂ = 2.53 volts

V₃ = V - V₁ = 12 - 2.53 = 9.47 volts

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U₁ = 1/2 C₁ V₁² = 0.5 * 10 * 10^-6 * 2.53² = 3.2 * 10^-5 J

U₂ = 1/2 C₂ V₂² = 0.5 * 5 * 10^-6 * 2.53² = 1.6 * 10^-5 J

U₃ = 1/2 C₃ V₃² = 0.5 * 4 * 10^-6 * 9.47² = 1.8 * 10^-4 J

Total energy = 1/2 C_equ V² = 0.5 * 3.16 * 10^-6 * 12² = 2.28 * 10^-4 J