In the figure a physical pendulum consists of a uniform soli

In the figure, a physical pendulum consists of a uniform solid disk (of radius R = 32.7 cm) supported in a vertical plane by a pivot located a distance d = 14.1 cm from the center of the disk. The disk is displaced by a small angle and released. What is the period of the resulting simple harmonic motion?

Solution

R = 32.7 cm = 0.327 m

d = 14.1 cm = 0.141 m

T = 2pi * [(R^2+2d^2)/(2gd)]^1/2 = 2*pi*((0.327^2 + 2*0.141^2)/(2*9.8*0.141))

= 1.447 s