please help will rate The hotel room rate in New York City i
please help will rate
The hotel room rate in New York City is normally distributed with a mean of $231 per night. Assume that the standard deviation is unknown.
If 25% of the New York City hotel room rates are more than $261 per night, what is the variance? (Remember the label.)
Solution
Here, the left tailed area for 261 is 1-0.25 = 0.75.
Thus, the corresponding z score to it is
z = 0.67448975
As
z = (x - u) / sigma
Then
sigma^2 = variance = [(x-u)/z]^2
Thus,
variance = ((261-231)/0.67448975)^2 = 1978.298406 $^2 [ANSWER]
