Anova table Solutiona Sum of squaresnxu2 Mean squares Sum of
Anova table
Solution
a) Sum of squares=n(xu)2
Mean squares= Sum of Squares/d.f.
d.f. = n-1
Where n is number of groups or total number of samples
x is sample value,
u is mean of that group
b) Critical value for Significance level of 5% = 3.8853,
So calculated value is greater then critical value the we can safely assume that mean of three group are unequal
Source of Variation | Sum of Squares | d.f. | Mean Squares | F |
Between | 570 | 2 | 285 | 51.82 |
Error | 66 | 12 | 5.5 | |
Total | 636 | 14 |
