A bar having a length of 5 in and crosssectional area of 05
A bar having a length of 5 in and cross-sectional area of 0.5 in^2 is subjected to an axial forte of 8000 lb. If the bar stretches 0.0025 in., determine the modulus of elasticity of the material. The material has linear-elastic behavior
Solution
Modulus of elasticity = FL/ A * dL
E = 8000*5/ 0.5*0.0025
E = 32000000 Psi
E = 32000 ksi
