In each one of Exercises 2326 you are asked to find the area

In each one of Exercises 23-26 you are asked to find the area of the triangle Delta ADC, based on the given information. (Do not solve the triangle!)

23) A= 35 deg . b= 13cm C=45 deg

B = 180-35-45 = 100 deg

Applying sine rule:

a/sinA = b/sinB

a/sin83 = b/sin100

15/sin83 = b/sin100

b = 14.883 cm

Again: c/sinC = a/sinA

c = sin45*15/sin35 = 18.492

24 .) A= 44 deg B= 55deg C= 10 cm

Angle C = 180-44-55 = 100 deg

Applying sine rule:

c/sinC = a/sinA

a= (c/sinC)*sinA = (10/sin100)sin44 = 7.036 cm

Again : b = sinB(c/sinC) = sin55*(10/sin100) =8.317 cm