57x372xSolutionWe have 57x3 72x Now on taking logarithm of b

5^(7x+3)=7^(2x)

We have 5^(7x+3) =7^2x.

Now, on taking logarithm of both the sides, we get log 5^(7x+3) = log7^2x or, (7x+3)log 5 = 2x log 7 (as log mⁿ = nlog m)

Or, (7x+3)= 2x(log 7)/(log 5) = 2x* (0.84509804)/(0.698970004)= 2.418123911 x or, (7-2.418123911)x =-3 or, 4.581877089x = -3 so that x = -3/4.581877089=-0.654753486 or, x = -0.655 ( on rounding off to 3 decimal places).

5^(7x+3)=7^(2x)SolutionWe have 5(7x+3) =72x. Now, on taking logarithm of both the sides, we get log 5(7x+3) = log72x or, (7x+3)log 5 = 2x log 7 (as log mn = nlo

57x372xSolutionWe have 57x3 72x Now on taking logarithm of b

Solution

Get Help Now

Submit a Take Down Notice