You are studying a population of milkweeds and you find the

You are studying a population of milkweeds and you find the following allele frequencies: f(A_1A_1) = 0.36 f(A_lA_2) = 0.48 f(A_2A_2) = 0.16 If the fitness of the homozygote (w_11) is 0.9 and the average fitness of the population is 0.916, what do we expect the new frequency of the A_1A_1 homozygote genotype to be in the next generation? 0.35 0.40 0.50 0.60 0.91

Solution

The correct answer is: 0.35

Calculation:

New frequency of A1A1 homozygote genotype in the next generation will be:p²w₁₁ / W

where p² = f(A1A1)=0.36 ; w_{11 =} fitness of homozygote =0.9 ; W = average fitness = 0.916

So, 0.36 * 0.9 /0 .916 = 0.35 (ans )