33 The table below was obtained by using data for 40 males T
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The table below was obtained by using data for 40 males. The response (y) variable is weight (in pounds), and the predictor (x) variables are HT (height in inches), WAIST (waist circumference in cm), and CHOL (cholesterol in mg).
Predictor (x) Variables
P-value
R2
R2
Regression Equation
HT, WAIST, CHOL
0.000
0.873
0.862
y =?199+2.2?
HT+2.1?
WAIST?0.1
HT, WAIST
0.000
0.869
0.862
y =?219+2.06 HT+2.15 WAIST
HT, CHOL
0.002
0.302
0.264
y =?154+4.65 HT+0.00469 CHOL
WAIST, CHOL
0.000
0.793
0.782
y =?49.3+2.61 WAIST?0.0106 CHOL
HT
0.001
0.273
0.254
y =?139+4.55?
WAIST
0.000
0.790
0.785
y =?44.1+2.37?
CHOL
0.874
0.001
0.000
y =173?0.00233?
CHOL
If a male has a height of?
72?
in, a waist circumference of?
102?
cm, and a cholesterol level of?
263?
mg, what is the best predicted value of his weight?
The best predicted value of this male\'s weight is?
.
(Round to the nearest whole number as needed.)
| Predictor (x) Variables | P-value | R2 | Adjusted? R2 | Regression Equation |
| HT, WAIST, CHOL | 0.000 | 0.873 | 0.862 | y =?199+2.2? HT+2.1? WAIST?0.1 ?CHOL |
| HT, WAIST | 0.000 | 0.869 | 0.862 | y =?219+2.06 HT+2.15 WAIST |
| HT, CHOL | 0.002 | 0.302 | 0.264 | y =?154+4.65 HT+0.00469 CHOL |
| WAIST, CHOL | 0.000 | 0.793 | 0.782 | y =?49.3+2.61 WAIST?0.0106 CHOL |
| HT | 0.001 | 0.273 | 0.254 | y =?139+4.55? HT |
| WAIST | 0.000 | 0.790 | 0.785 | y =?44.1+2.37? WAIST |
| CHOL | 0.874 | 0.001 | 0.000 | y =173?0.00233? CHOL |
| If a male has a height of? 72? in, a waist circumference of? 102? cm, and a cholesterol level of? 263? mg, what is the best predicted value of his weight? The best predicted value of this male\'s weight is? . (Round to the nearest whole number as needed.) |
Solution
Best regression is y =?199+2.2*HT+2.1*WAIST?0.1*CHOL because its R square 0.873 is larger other R square values.
If a male has a height of?72?in, a waist circumference of?102?cm, and a cholesterol level of?263mg,
The best predicted value of this male\'s weight is
= ?199+2.2*72+2.1*102?0.1*263 = 147.3 pound


