Find the complex power supplied by the source on the left Th
Find the complex power supplied by the source on the left. The correct value is shown in the blue box as: Ss(bar)= 70.25+ j72.24 KVA
Xpovr sypplit 24kW Vs() 36kW 0.78 rnS la agg\'nj VA S70.25TA Solution
load 1:
p=24*10^3 watts.
VIcosq=24*10^3
220<0*I*0.85=24*10^3
I1=128.34 amps.
load 2:
p=36*10^3 watts.
VI*cosq=36*10^3
220<0*I*0.78=36*10^3
i2=209.79 amps.
vs=(0.09+j0.25)*(i1+i2)+220<0
vs=(0.09+j0.25)*(128.34+209.79)+220<0
vs=264.3<18.65 voltss.
complex power=vs*(I1+I2)
complex power=264.3<18.65*(128.34+209.79)=(84675.03+j28578.58) VA.
p=
