The depiction region of a PN junction widens as a reverse bi

The depiction region of a PN junction widens as a reverse bias applied to the terminals increases. True False Why? Assuming that a 10 kg pure silicon charge is used, what is the amount of boron that must be added to get the boron-doped silicon having a resistivity of 0.01 Ohm cm when one half of the ingot is grown? NOTE the molecular weight of boron is 10.81g/mole

Solution

7 Ans) a.True: Reason:Under reverse bias (P negative with respect to N), the potential drop (i.e., voltage) across the depletion region increases. In details, majority carriers are pushed away from the junction and leaving behind more charged ions. So the depletion region is widened