5 A new PV module note that the module is comprised of sever
Solution
Given Power output of the module under STC condition is Pm = 210 W;
From the I- V characterstic of PV module VOC = 50.1 V and ISC = 5.6 A at STC i.e 1000 W/m2 , 250C,1 air mass.
Maximum Power Point of PV module is Pm = Vm * Im = 210 V.
From the graph maximum power point Voltage is Vm = 40 V
Maximum power point Current Im = Pm / Vm = 210/40 = 5.25 A
Fill factor is defined as ratio of maximum point to VOC*ISC
F = Pm / (VOC * ISC) = 210 / (50.1 * 5.6) = 210/280.56 = 0.7485 ;
a) Energy Conversion efficiency is given by
%eta = ( Pm / (L*B*1000) ) *100
where L = 1.580 m is length of module and width of module is B = 0.812 m
%eta = ( 210 / (1.58*0.812*1000) ) *100 = 16.3683 %
b) No.of modules required to meet load of 4.2 kW is
N = 4200/210 = 20 panels.
No.of panels connected in series is ns = VDCT / Voc = 300 / 40 = 7.5 = 8 panels.
No.of Panels connected in Parallel is np = 4200/(300*6.25) = 2.24 = 3 strings consisting of 8 panels each.
c) Each module weight is 15 Kg . Total weight of modules is 24*15 = 360 Kg and mounting structure is of weight same as modules i.e 360 Kg.
Total weight on building is WT = 720 Kg.
