You have isolated five T4 rllA mutants each of which contain
Solution
* strain B — which supports the growth of all viruses thus giving the total number of viruses liberated.
* strain K — on which only wild-type viruses can grow.
rII mutants as well as wild-type T4 can infect and complete their life cycle in a strain of E. coli B. rII mutants can also infect E. coli K, but cannot complete their life cycle in strain K.
Any mutation that recombines with deletion 1 must be to the right of the deletion 1, any mutation that recombines with deletion 2 must be to the right of deletion 2, and so forth.
Let’s look at point mutation a. It recombines with deletions 2,4 and 5 but not with deletion 1,3. Therefore, it is to the right of deletions 2,4, and 5 but not to the right of deletion 1,3. We can therefore place point mutation a in the right of deletion 1 .
Point mutation b recombines with deletions 1,4 and 5 and must be to the right of them. It does not recombine with deletions 2 and 3.
Point mutation c recombines with deletions 2,4 and is to the right of 2,4 deletions,It does not recombine with deletions 1,3,5.
Point mutation d recombines with deletions 1,2 and 4 and must be to the right of them. It does not recombine with deletions 3 and 5.
Point mutation e recombines with deletions 1,5 and must be to the right of them. It does not recombine with deletions 2,3,4.
Point mutation f recombines with deletions 2,5 and must be to the right of them. It does not recombine with deletions 1,3,4.
Point mutation g recombines with deletions 1,2,5 and must be to the right of them. It does not recombine with deletions 3,4.
