A piece of commercial real estate is priced at 450 per squre

A piece of commercial real estate is priced at $4.50 per squre foot. Find the cost, to the nearest cent, of a triangular lot measuring 320 yd by 210 yd by 410 yd.

Solution

1 yard = 3 foot

area of triangle ;

S= semi-perimeter = (210 + 410 + 320)/2 = 470
Area = sqrt(470(470-210)*(470-410)(470-320) ) = 33163.2 yd^2=298467 sq foot

1 sq foot = 4.5$

298467 sq ft= 298467*4.5=1343101.5$ ans.