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4.30 If P(A) = 0.3, P(B) = 0.4, and if A and B are mutually exclusive events, find: a. P(A) c. P(A or B) b. P(B) d. P(A and B)

Solution

A)

P(A\') = 1 - P(A) = 1 - 0.3 = 0.7 [ANSWER]

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b)

P(B\') = 1 - P(B) = 1 - 0.4 = 0.6 [ANSWER]

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c)

As they are mutually exclusive, P(A n B) = 0. Thus,

P(A or B) = P(A) + P(B) - P(A n B) = 0.3 + 0.4 - 0

P(A or B) = 0.7 [ANSWER]

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d)
As they are mutually exclusive, P(A n B) = 0.

P(A n B) = 0 [ANSWER]