Consider the following probability table to answer the quest
Consider the following probability table to answer the questions 2 and 3.
Find the mean or expected value of this probability distribution.
Find the standard deviation of this probability distribution.
x
P(x)
4
0.01
8
0.03
12
0.05
20
0.09
24
0.50
25
0.28
26
0.04
| x | P(x) |
| 4 | 0.01 |
| 8 | 0.03 |
| 12 | 0.05 |
| 20 | 0.09 |
| 24 | 0.50 |
| 25 | 0.28 |
| 26 | 0.04 |
Solution
Consider the table:
Thus,
E(x) = 22.72 [ANSWER, MEAN]
Var(x) = E(x^2) - E(x)^2 = 19.1216
s(x) = 4.372825174 [ANSWER, STANDARD DEVIATION]
| x | P(x) | x P(x) | x^2 P(x) |
| 4 | 0.01 | 0.04 | 0.16 |
| 8 | 0.03 | 0.24 | 1.92 |
| 12 | 0.05 | 0.6 | 7.2 |
| 20 | 0.09 | 1.8 | 36 |
| 24 | 0.5 | 12 | 288 |
| 25 | 0.28 | 7 | 175 |
| 26 | 0.04 | 1.04 | 27.04 |

