A 42109 C charged object is 61 cm along a horizontal line to

A +4.2×109 C charged object is 6.1 cm along a horizontal line toward the right of a -3.3×109 C charged object.

**Determine the E field at a point 4.0 cm to the left of the negative charge.

Express your answer to two significant figures and include the appropriate units.

q1= 4.2 * 10^-9 C

q2 = -3.3 * 10^-9 C

point A whre field needs to be determined is 4 cm from negative charge and 10.1 cm from positive charge

SO E = kq1/r1^2 + kq2/r2^2 = k (4.2 * 10^-9 /(10.1*10^-2)^2) - 3.3 * 10^-9/(4*10^-2)^2)

=1.48 * 10^4 N/c towards charges