solve the following system of equations maximize profit4x6y
solve the following system of equations maximize profit=4x+6y maximize profit = 4x + 6y subject to: x + 2y = 0
Solution
Profit Function
Z = 4x + 6y
Constraint
x + 2y = 0
substituting x=-2y in the equation we get
Z = 4(-2y) + 6y = -2y
Hence the profit can be as high as possible depending upon the value of y, the problem is not complete please check the problem
