Assume a test specimen crosssectional area of 003 in2 and a

Assume a test specimen cross-sectional area of 0.03 in^2 and a gage length of 1.5 inches. Show All Work!

Load (lbs) 3,000 Material 1 Material 2 2,550 1,650 1,114 X Material 3 0.04 0.10 0.25 0.35 Displacement (inch)

Tensile strength = Load taken to break the wire/ Cross sectional area

= 3000 lbs/ .03 in^2

= 100000 lbs/in^2.

As there is not yield point and the material breaks from the elastic phaze the ulimate tensile strenght is equal to yield strength.

Elongation at failure = .04 inches

Strain to failure = 0.04/1.5 = 0.026

The material is brittle as it breaks before going to the plastic stage.