Find the equation of the tangent line to the graph of the gi

Find the equation of the tangent line to the graph of the given function at the give given value of x.

f(x) = (3x^2 - 4)^4/3; x = 2

f(x)^\' =(4/3)*(3x^2 - 4)1/3 (6x)

f(2)^\'=32

f(2) = 64/3

eqn of tangent =( y-64/3)/(x-2) = 32

$Find the equation of the tangent line to the graph of the given function at the give given value of x. f(x) = (3x^2 - 4)^4/3; x = 2Solutionf(x)\' =(4/3)*(3x^2 -$

Find the equation of the tangent line to the graph of the gi

Solution

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