Assume that X is a binomial random variable with n 16 and p
Assume that X is a binomial random variable with n = 16 and p = 0.66. Calculate the following probabilities. (Round your intermediate and final answers to 4 decimal places.)
| a. P(X = 15) | |
| b. P(X = 14) | |
| c. P(X 14) |
Solution
a)
Note that the probability of x successes out of n trials is
P(n, x) = nCx p^x (1 - p)^(n - x)
where
n = number of trials = 16
p = the probability of a success = 0.66
x = the number of successes = 15
Thus, the probability is
P ( 15 ) = 0.010684592 = 0.0107 [answer]
b)
Note that the probability of x successes out of n trials is
P(n, x) = nCx p^x (1 - p)^(n - x)
where
n = number of trials = 16
p = the probability of a success = 0.66
x = the number of successes = 14
Thus, the probability is
P ( 14 ) = 0.041281377 = 0.0413 [answer]
c)
Note that P(at least x) = 1 - P(at most x - 1).
Using a cumulative binomial distribution table or technology, matching
n = number of trials = 16
p = the probability of a success = 0.66
x = our critical value of successes = 14
Then the cumulative probability of P(at most x - 1) from a table/technology is
P(at most 13 ) = 0.946737739
Thus, the probability of at least 14 successes is
P(at least 14 ) = 0.053262261 = 0.0533 [answer]
