Find two numbers a and b whose sum ab is 8 and whose differe

Find two numbers a and b whose sum a+b is -8 and whose difference ab is -2.

a + b = -8 ---> equation ONE

a - b = -2 ---> equation TWO

Notice first eqn has +b and 2nd equation has -b.

So, we can add them and thereby, b gets eliminated

Adding :

a + b + (a - b) = -8 + (-2)

2a = -10

a = -10/2

a = -5

Now, plug this back into equation 1(or equation 2) :

a + b = -8

-5 + b = -8

b = -8 + 5

b = -3

So, solution is :

a = -5 , b = -3 ----> ANSWER