5 cos 12 i sin 12 6 cos 149 i sin 149 Give anwser is

5 [ cos (12°) + i sin (12°) ] * 6 [ cos (149°) + i sin (149°) ]

Give anwser is polar form

Solution

e^{i x} = cos( x ) + i sin( x )

so,

5( eⁱ¹² ) x 6( e149ⁱ )

= 30 . e¹⁶¹ⁱ =

30 (cos 161 + i sin 161) = answer