A bird fly 200kmhrTwo trains coming oppositely one 100kmhr o

A bird fly 200km/hr.Two trains coming oppositely one 100km/hr, other 50km/hr.
Total distace between the trains starting point is 450km.So the bird is flying to and fro in the train line.How long distance the bird travel when the trains
meet each other.

Solution

distane getween trains is 450 km.

one train travels 100 km / hr.

other train travels 50 km / hr.

they will meet when the total distance traveled by both of them is equal to 450 km.

equation for distance is R*T = D.

This means that rate * time = distance.

We know the rates.
We know the distance.
We know that the time that each train travels will be the same.

We let h = the time each train travels.

train 1 travels 100 km / hr * h hours.
train 2 travels 50 km / hr * h hours.

the total distance they travel is 450 km.

our equation is:

100 * h + 50 * h = 450

combine like terms to get:

150 * h = 450

divide both sides by 50 to get:

h = 450/150 = 3

They will meet in 3 hours.

train 1 will have traveled 100 * 3 = 300 km.
train 2 will have traveled 50 * 3 = 150 km.

total distance traveled by both trains is equal to 450 km.

the bird was flying at 200 km/h.

in the same 3 hours the bird flew a total of 200 * 3 = 600 km.

bird flies 450 km in one direction, then travels back 150 km when the trains meet.

450 + 150 = 600 km.

if the bird started at the end of the faster train, the bird will be directly overhead when the trains meet.

if the bird started at the end of the slower train, the bird will not be anywhere near the trains when they meet.

here\'s what it looks like: