Use the Squeeze Theorem to find Solution0x2 now let gxx hxx2

Solution

0<sin²x<1

1<1+sin²x<2

1>1/(1+sin²x)>1/2

x>x/(1+sin²x)>x/2

now let g(x)=x

h(x)=x/2

f(x)=x/(1+sin²x)

limit x>0+ g(x)=0

limit x>0+ h(x)=0

so by squeeze theorem:limit x>0+ f(x)=limitx>0+ h(x)=0

so answer is 0