How do I find the volume of the solid obtained by revolving

How do I find the volume of the solid obtained by revolving the region bounded by the curves y=2-x^2, y=0, and x=0 about the y-axis

solve for x: x=sqrt(2-y)
pi*integral from 0 to 2 of (sqrt(2-y))^2
pi*integral from 0 to 2 of (2-y)
pi*(2y-1/2*y^2) form 0 to 2
pi*(4-2)=2*pi or about 6.28