A sample of n 9 scores has a mean of M 46 and a variance o

A sample of n = 9 scores has a mean of M = 46 and a variance of s² = 36. What is the estimated standard error for this sample?

Solution

Standard Error= sd/ Sqrt(n)
Where,
sd = Standard Deviation
n = Sample Size

Standard deviation( sd )= Sqrt(Varaiance) = Sqrt(36) = 6
Sample Size(n)= 9
Standard Error = ( 6/ Sqrt ( 9) )
= 2