Let G a epsilon R 1 SolutionGiven a b ab 1ab here a is
Let G = {a epsilon R : = -1
Solution
Given a * b = a+b/ (1+ab)
here a is in between -1 and 1
and G depends on a
(G,*) is
initially taking a=-1
-1 * b = ( -1 + b) / ( 1 - b)
-b = b - 1 / 1 -b
taking a=1
b = 1+b/ 1+b
where b=1
now taking (R,+)
R is an real number between -1 and 1
taking R= -1 and R=1
initially taking a=-1
-1 * b = ( -1 + b) / ( 1 - b)
-b = b - 1 / 1 -b
taking a=1
b = 1+b/ 1+b
where b=1
we obtain the same answer as above
so (G , *) = (R,+)
