3 Charbeneau Problem 329 A we of radius 05 ft produces water

3. Charbeneau (Problem 3.2.9): A we of radius 0.5 ft produces water from an unconfined aquifer with K-10 ft/day. The well is located 900 ft from a large water body that acts as a constant head boundary. If the saturated thickness of the aquifer at the water body is 80 ft, what is the maximum production rate of the well?

Solution

  Solution:-

Given

L = 900 feet

r = 0.5 feet

s = 80 feet

K = 10 ft/day

Production rate of well(Q) = 2.72*K*s *(L + s/2)/(log10(R/r))

Q = 2.72 * 10 *80*(900 +80/2)/(log(960/0.5))

Q = 622.9827 *103 feet3/day Answer

 3. Charbeneau (Problem 3.2.9): A we of radius 0.5 ft produces water from an unconfined aquifer with K-10 ft/day. The well is located 900 ft from a large water

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