A power cycle operates with work of the cycle of 800 Btu and
Solution
5-----
Thermal efficiency of a system = W/Q
= 800 /1800 = 44.44
So thermal efficiency is 44.44 %.
6----
A heat pump is a device which applies external work to extract an amount of heat QC from a cold reservoir and delivers heat QH to a hot reservoir.
A heat pump is subject to the same limitations from the second law of thermodynamics as any other heat engine and therefore a maximum efficiency can be calculated from the Carnot cycle. Heat Pumps are usually characterized by a coefficient of performance which is the number of units of energy delivered to the hot reservoir per unit work input.
Given QH= 40,000 Btu
COP = 2.8
COP = QH / W
W= QH / COP = 40,000/2.8 = 14,285 Btu
7 ----
Power charge for ,1 hr and 1000,000 Btu = 3 Dolllar
So Power charge for , 8 hr and 1000,000 Btu = 24 Dollar
As in Problem No 6 - amount required to heat pump is 14,285 Btu
So Power charge for the 8 hr , 14, 285 Btu = [24 * 14,285] / [1000,000]
= 0.3485 Dollar
8--------
Force = 60 lbf
5 miles in 45 min
So 1 miles in 9min
So velocity v= 9 miles/min
Total energy expenditure = energy expenditure value of activity x duration of activity in minutes x your body weight in pounds
Total energy expenditure = 0.09*45*60
= 243 kCal

