Solve log125 x 29 25 10 3 square root 25 square root 125 No

Solve: log_125 x = 2/9 25 10 3 square root 25 square root 125 None of the above

Solution

log125x =2/9

by properties of logarithams if logba =c then a =bc

x =1252/9

x =(53)2/9

by law of exponents (am)n=amn

x =53*2/9

x =52/3

x=(52)1/3

x=251/3

x=325

option C

 Solve: log_125 x = 2/9 25 10 3 square root 25 square root 125 None of the aboveSolutionlog125x =2/9 by properties of logarithams if logba =c then a =bc x =1252

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