In Fig 1 below R 8 ohm L 15 mH Vdc 12 V and Vst 50 30 c
In Fig. 1 below, R = 8 ohm, L = 15 mH, V_dc = 12 V, and V_s(t) = 50 + 30 cos (4pi60t) + 10 cos (8pi60t) V. Determine the power absorbed by each component.
Solution
Xl= j2*pi*f*L= j2*pi*180*15*10^-3 = j16.96ohms
Req= (8+j16.96)ohms
Vin= 60-12= 48+j0
I(t)= 1.09-2.31j
power absorbed by resistor= I2R=-33.3-40.4j
inductor= 1/2*L*I2 =1/2*15*10^-3*(-4.14-5.03j)= -0.031-0.037j
