Which of these binary relations on integers are reflexive ir
Solution
Answer :
a) Define the relation R by R(x,y) iff y = x + 1
R is not reflexive as x x + 1
R is irreflexive as x x + 1 for every x
R is not symmetric as y = x+ 1 implies that x y + 1
R is antisymmetric as if y = x + 1 and x = y + 1 we have x = y
R is not transitive as if y = x + 1 and x = z + 1 then y z + 1
(b) Define the relation R by R(x,y) iff x divides y evenly
R is reflexive as x divides x evenly for all x
R is not irrelexive
R is not symmetric as 2 divides 4 evenly but 4 does not divide 2 evenly
R is antisymmetric as if x divides y evenly and y divides x evenly then x = y
R is transitive as if x divides y evenly and y divides z evenly then x divides z
c) Define the relation by R(x,y) if y = 2dx for some non negative integer d
R is relexive since for every x we can write x = 2(0) x = x for some non negative integer zero.
R is not irreflexive
R is not symmetric as 20 = 22 .(5) but 5 22 .(20)
R is anti symmetric as if y = 2dx and x = 2d y for some non negative integer d then x = y
R is not transitive as if y = 2dx and x = 2d z for some non negative integer d then y 2d z for some non negative integer
D) Define the relation R by R(x,y) if x and y are both divisible by 17
R is not reflexive as for every x ; x is not divisible by 17.
R is not irreflexive as x = 34 is divisible by 17.
R is symmetric if x and y are both divisible by 17 then y and x are both divisible by 17.
R is not anti symmetric as if 17 and 34 are divisible by 17 and 34 and 17 are divisible by 17 but 17 34
R is transitive as if x and y are divisible by 17 ;and y and z are divisible by 17 then x and z are divisible by 17.
