Complete the following functions which calculates the summat

Complete the following functions, which calculates the summation as in the equation sum = 1/n + 2/n - 1 + 3/n - 2 + ... + n/1 #include using namespace std; double (int n);//returns void (double, int n);//stores result in double (double i, int n);//recursive void (int n);//use global variable//Global Variable int main() {int n; cout

Solution

double sum1(int n)

{

double s=0.0;

for(int i=1;i<=n;i++)

{

s=s+(i/(n-i+1));

}

return s;

}

double sum3(double i,int n)

{

i=0.0;

for(int j=1;j<=n;j++)

{

i=i+(j/(n-j+1));

}

return i;

}

void sum4(int n)

{

double i=0.0;

for(int j=1;j<=n;j++)

{

i=i+(j/(n-j+1));

}

printf(\"%lf\",i);

}

void sum2(double sum,int n)

{

sum=0.0;

for(int j=1;j<=n;j++)

{

sum=sum+(j/(n-j+1));

}

printf(\"%lf\",sum);

}

 Complete the following functions, which calculates the summation as in the equation sum = 1/n + 2/n - 1 + 3/n - 2 + ... + n/1 #include using namespace std; dou
 Complete the following functions, which calculates the summation as in the equation sum = 1/n + 2/n - 1 + 3/n - 2 + ... + n/1 #include using namespace std; dou

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