Mechanics of materials 5 A tensile test is performed on an a

Mechanics of materials

5. A tensile test is performed on an aluminum specimen that is 0.45 inch in diameter using a gage length of 2 inch, as shown in the figure a) When the load is increased by an amount P = 2 kips, the distance between gage marks increases by an amount 0.002 inch. a) Calculate the modulus of elasticity for this specimen. b) If the proportional limit stress for this specimen is 60 ksi, what is the distance between gage marks at this value of stress? 2 in. 0.45 in

Solution

a) CHANGE IN LENGTH = PL/AE

0.002= 2*2/(0.159*E)

E = 12578.6 Ksi.

B) CHange in length = 60*2/12578.6

=0.00954 in.

Distance between gauge marks = L+change in length

=2+0.00954

=2.00954