A 31cmdiameter parallelplate capacitor has a 21 mm spacing T
A 3.1-cm-diameter parallel-plate capacitor has a 2.1 mm spacing. The electric field strength inside the capacitor is 1.1×105 V/m .
Part A What is the potential difference across the capacitor?
Part B How much charge is on each plate?
Solution
a) electric field , E = 1.1 *10^5 V/m
potential difference = E * distance
potential difference = 1.1 *10^5 * 2.1 *10^-3 V
potential difference = 231 V
b)
charge on each plate = V * epsilon * area/d
charge on each plate = (231 * 8.854 *10^-12 * 3.14*(0.031/2)^2)/(2.1*10^-3)
charge on each plate = 7.34 *10^-10 C
