Use this information for Question 1 and 2 In horses a black

Use this information for Question 1 and 2. In horses, a black coat (B) is dominant brown coat (b) and being a trotter (T) is dominant to being a pacer (t).

1.A black pacer crossed with a brown trotter. The offspring is a brown pacer. Give the genotype of all these horses.

2.A black pacer mated to a brown trotter produces a black trotter offspring. Give all possible genotypes of this offspring

Solution

1.A black pacer crossed with a brown trotter. The offspring is a brown pacer. Give the genotype of all these horses.

Parental genotypes = Bbtt x bbTt

Punnett square

Bt

bt

bT

BbTt (black trotter)

bbTt (brown trotter)

bt

Bbtt (black pacer)

bbtt (brown pacer)

2.A black pacer mated to a brown trotter produces a black trotter offspring. Give all possible genotypes of this offspring

Scenario 1.

Parental genotypes = Bbtt x bbTt

Punnett square

Bt

bt

bT

BbTt (black trotter)

bbTt (brown trotter)

bt

Bbtt (black pacer)

bbtt (brown pacer)

Scenario 2.

Parental genotypes = BBtt x bbTT

Punnett square

Bt

bT

BbTt (black trotter)