Find the value of z score that separates the top 3 of the st

Find the value of z score that separates the top 3% of the standard normal curve

Solution

Normal Distribution
Mean ( u ) =0
Standard Deviation ( sd )=1
Normal Distribution = Z= X- u / sd ~ N(0,1)                  
P ( Z > x ) = 0.03
Value of z to the cumulative probability of 0.03 from normal table is 1.88
P( x-u/ (s.d) > x - 0/1) = 0.03
That is, ( x - 0/1) = 1.88
--> x = 1.88 * 1+0 = 1.881