Use the normal distribution for this question The mean maxim

Use the normal distribution for this question. The mean maximum aerobic power (VO2MAX) score for women ages 20 to 29 is 36 ml/min/kg with a standard deviation of 7 ml/min/kg. Find the probability of a woman between the ages of 20 to 29 having a VO2MAX score of greater than 45 ml/min/kg.

Solution

We first get the z score for the critical value. As z = (x - u) / s, then as          
          
x = critical value =    45      
u = mean =    36      
          
s = standard deviation =    7      
          
Thus,          
          
z = (x - u) / s =    1.285714286      
          
Thus, using a table/technology, the right tailed area of this is          
          
P(z >   1.285714286   ) =    0.099271397 [ANSWER]

Use the normal distribution for this question. The mean maximum aerobic power (VO2MAX) score for women ages 20 to 29 is 36 ml/min/kg with a standard deviation o

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