Find the area under the standard normal curve between z 171
Solution
2.
z1 = lower z score = -1.71
z2 = upper z score = 1.24
Using table/technology, the left tailed areas between these z scores is
P(z < z1) = 0.043632937
P(z < z2) = 0.892512303
Thus, the area between them, by subtracting these areas, is
P(z1 < z < z2) = 0.848879366 [answer]
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3.
z1 = lower z score = -2.3
z2 = upper z score = 1.53
Using table/technology, the left tailed areas between these z scores is
P(z < z1) = 0.01072411
P(z < z2) = 0.936991636
Thus, the area between them, by subtracting these areas, is
P(z1 < z < z2) = 0.926267526 [answer]
