Calculate the Delta G for the following scenarios and state
Solution
4. a
A concentration of K+ inside the cell is 30X more than outside.
a body temperature of 37°C, so an absolute temperature of 37 + 273 = 310°K, and
G = RT ln( X in / X out)
G = the change in free energy
R = 2 ( gas constant)
T = K , absolute temperature = C + 273
Ln = natural log
Xin = internal ion conc
X out = external ion conc
Therefore
G = (2)(273+37) x ln (30x/1x)
= (2)(310) x ln (30)
= (620)(3.4) = +2108 cal/mole
= +2.1 kcal/mole
Since the G is positive, it requires energy.
4b. This time we have membrane potential. = -60mV
G = (R)(T) x ln(30x/1x) + (z)(F)(Vm)
= (2)(273+37) x ln (30) + (+1)(23,062)(-0.06)
= (620) x (3.4) + (-1387)
=+ 721cal /mol
= + 0.721 Kcal/ mol
Since the G is positive, it requires energy to transport.
4c. X out = 145mM
X in = 12mM
T = 25C
V= -90mV
Z = -1
G = (2)(273+25) x ln (12mM / 145mM) + (-1)(23,062)(-0.09)
= 596 X (-2.52) + (2075)
= -1501 + 2075
G = +573.
Since the G is positive, it requires energy to transport.
4d.
G = - 2.303 RT pH + (z)(F)(Vm)===> (NOTE: DpH = pHin - pHout )
= -2.303 (2)(273+25) + (+1) (23,062) (-0.180)
= -1372 + (-4151)
= - 5523cal /mol
=-5.5Kcal/mol
Since the G is negative, the reaction is spontaneous.

