Node Node Node A RE R3C Ri R3 Re Node SolutionAns Using KVLK

Node Node Node A. RE R3-C Ri R3 Re Node

Solution

Ans)

Using KVL(Kirchoff\'s Voltage law ) We write following equations for 2 loops

VS1=I1*R1 + I2* R2---------1

I3*(R3+R4) -I2* R2=0-------2

Using KCl we have I1=I2+I3

and I2=I1-I3 from above ,subsituting this in equations 1 and 2 we get

VS1=I1*R1 +(I1-I3)*R2

VS1=I1(R1+R2) -I3*R2-------------3

I3*(R3+R4)-(I1-I3)*R2=0

I3(R3+R4+R2) - I1*R2=0------------4

substituting Values in 3 and 4 gives

20=I1(2k+6k)-I3*6k

20=I1*8k -I3*6k --------------3

0 =-I1*6k+I3(6k+2k+1k)

0=-I1*6k+I3*9k------------------4

Solving equations 3 and 4 we have

a)

I1=5 mA

I3=3.33 mA

I2=I1-I3=5-3.33=1.67 mA

b)

Power in R4= I3^2*R4=(3.33m)^2*1k=0.01 W