A thin insulating rod is bent into a semicircular arc of rad

A thin insulating rod is bent into a semicircular arc of radius a, and a total electric charge Q is distributed uniformly along the rod. Calculate the potential at the center of curvature of the arc if the potential is assumed to be zero at infinity. (Use any variable or symbol stated above along with the following as necessary: 0.)

V

Solution

dQ=(Q/)d

V=integration of KdQ/r from 0 to

V=(kQ/a)(-0)

V=kQ/a=(1/4₀)Q/a