ch222 G Electric Charge Is Distribut Welcome to PHY 1963P B

ch22-2 G Electric Charge Is Distribut Welcome to PHY 1963-P × Bb C www.webassign.net/web/Student/Assignment-Responses/last?dep=13477515 3. 1.75/2 points | Previous Answers YF13 22.P.064. 7/15 Submissions Used My Notes Ask Your Teacher Charge is uniformly distributed over each of two spherical volumes with radius R. The left-hand sphere has positive charge Q and the right-hand sphere has negative charge -Q. One sphere of charge is centered at the origin and the other at x 2R (see figure below). Find the magnitude and direction of the net electric field due to these two distributions of charge at the following points on the x-axis. (Use any variable or symbol stated above along with the following as necessary: 0 0 (a) x = 0 magnitude direction (b) x = R/2 170 magnitude . direction itive x (c) x = R 20 magnitude direction sitive x (d)x = 3R 80 magnitude direction

Solution

As you have got the answers for parts A, B and C correct, I assume you need an explanation for part D.

We know that for a charged sphere with charge Q, electric field at any point lying outside of it can be given as

E = Q/ 4 oR^2 also, for positive charge it is directed away from the sphere while for negative charge it is directed towards the sphere.

Now for x = 3R, we have a positively charged sphere centres at x = 0 and a negatively charged one centres at x = 2R

Hence they will counter each other\'s electric field. Therefore the net electric field at x = 3R will be given as:

E = Q / 4 o [1/9R^2 - 1/R^2] = -8Q / 36 oR^2

Therefore the magnitude would 8Q / 36 oR^2 and direction would be negative x axis

NOTE: You need to enter the magnitude. As in try and enter the value without negative sign.