Let logb3 05646 logb4 07124 and logb5 08271 Using these v

Let log_b(3) = 0.5646, log_b(4) = 0.7124, and log_b(5) = 0.8271. Using these values, evaluate log_b(5/3).

Solution

solution:

log b(5/3)=logb(5)-logb(3)

Given logb(5)=0.8271

logb(3)=0.5646

=0.8271-0.5646

=0.2625