Suppose a speech signal is quantized with 8 bits per sample

Suppose a speech signal is quantized with 8 bits per sample. Assuming that the range of quantization amplitudes is matched to the signal amplitude, what is the SNR, measured in dB, of the speech signal?

Solution

answer of q12.

we know that SNR(Signal to noise ratio) is

S/N= (3P/x_max2) . 2^2v

here P is the power normalised signal power, x_max is maximum range in positive value of the linear quantizer, v is the number of bits per sample.

Here it is assumed that quantization amplitude and signal amplitude are mathced.

So, if amploitude of the speech signal is A_m then,

Signal P= Am²/2= x_max²/2

Now S/N= ((3x_max²)/2 x_max² ) .2^2.8=(3/2) 2¹⁶⁼98304

S/N in dB= 10 log(S/N)= 49.92 dB