Using the Standard Normal Table determine the proportion of

Using the Standard Normal Table, determine the proportion of the area under the normal curve that falls between z = -.30 and z = -.80.

Solution

z1 = lower z score =    -0.3      
z2 = upper z score =     -0.8      
          
Using table/technology, the left tailed areas between these z scores is          
          
P(z < z1) =    0.3821      
P(z < z2) =    0.2119      
          
Thus, the area between them, by subtracting these areas, is          
          
P(z1 < z < z2) =    0.1702 [ANSWER]